Base | Representation |
---|---|
bin | 11000100011101101000100… |
… | …10101011100100000111011 |
3 | 21002012200002010110122000012 |
4 | 30101312202111130200323 |
5 | 24034242323404442134 |
6 | 310504443440332135 |
7 | 14242420201401035 |
oct | 1421664225344073 |
9 | 232180063418005 |
10 | 54003347343419 |
11 | 16230766790381 |
12 | 608226391404b |
13 | 2419655b68b96 |
14 | d49ac1328c55 |
15 | 639b3e9206ce |
hex | 311da255c83b |
54003347343419 has 2 divisors, whose sum is σ = 54003347343420. Its totient is φ = 54003347343418.
The previous prime is 54003347343371. The next prime is 54003347343469. The reversal of 54003347343419 is 91434374330045.
It is an a-pointer prime, because the next prime (54003347343469) can be obtained adding 54003347343419 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54003347343419 - 228 = 54003078907963 is a prime.
It is a super-2 number, since 2×540033473434192 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54003347343469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27001673671709 + 27001673671710.
It is an arithmetic number, because the mean of its divisors is an integer number (27001673671710).
Almost surely, 254003347343419 is an apocalyptic number.
54003347343419 is a deficient number, since it is larger than the sum of its proper divisors (1).
54003347343419 is an equidigital number, since it uses as much as digits as its factorization.
54003347343419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 50.
The spelling of 54003347343419 in words is "fifty-four trillion, three billion, three hundred forty-seven million, three hundred forty-three thousand, four hundred nineteen".
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