540041312333 has 2 divisors, whose sum is σ = 540041312334. Its totient is φ = 540041312332.

The previous prime is 540041312309. The next prime is 540041312347. The reversal of 540041312333 is 333213140045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 440148652969 + 99892659364 = 663437^2 + 316058^2 .

It is a cyclic number.

It is not a de Polignac number, because 540041312333 - 2⁸ = 540041312077 is a prime.

It is a super-4 number, since 4×540041312333⁴ (a number of 48 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 540041312296 and 540041312305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (540041312303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270020656166 + 270020656167.

It is an arithmetic number, because the mean of its divisors is an integer number (270020656167).

Almost surely, 2^540041312333 is an apocalyptic number.

It is an amenable number.

540041312333 is a deficient number, since it is larger than the sum of its proper divisors (1).

540041312333 is an equidigital number, since it uses as much as digits as its factorization.

540041312333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 540041312333 its reverse (333213140045), we get a palindrome (873254452378).

The spelling of 540041312333 in words is "five hundred forty billion, forty-one million, three hundred twelve thousand, three hundred thirty-three".