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540053331203153 is a prime number
BaseRepresentation
bin111101011001011001111011…
…0111101110101010001010001
32121211011121001012120111000102
41322302303312331311101101
51031241213210242000103
65152333024134502145
7221516364665665625
oct17262636675652121
92554147035514012
10540053331203153
11147094371337149
12506a1b53b04955
131a245a6cbb6ca1
149750a13845185
15426805e677e88
hex1eb2cf6f75451

540053331203153 has 2 divisors, whose sum is σ = 540053331203154. Its totient is φ = 540053331203152.

The previous prime is 540053331203101. The next prime is 540053331203207. The reversal of 540053331203153 is 351302133350045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 513286542365584 + 26766788837569 = 22655828^2 + 5173663^2 .

It is a cyclic number.

It is not a de Polignac number, because 540053331203153 - 222 = 540053327008849 is a prime.

It is not a weakly prime, because it can be changed into another prime (540053331203653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270026665601576 + 270026665601577.

It is an arithmetic number, because the mean of its divisors is an integer number (270026665601577).

Almost surely, 2540053331203153 is an apocalyptic number.

It is an amenable number.

540053331203153 is a deficient number, since it is larger than the sum of its proper divisors (1).

540053331203153 is an equidigital number, since it uses as much as digits as its factorization.

540053331203153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 38.

Adding to 540053331203153 its reverse (351302133350045), we get a palindrome (891355464553198).

The spelling of 540053331203153 in words is "five hundred forty trillion, fifty-three billion, three hundred thirty-one million, two hundred three thousand, one hundred fifty-three".