Base | Representation |
---|---|
bin | 11000100011111011111011… |
… | …10110010011100010011111 |
3 | 21002020102200010002102200201 |
4 | 30101331331312103202133 |
5 | 24034410143213310012 |
6 | 310512243224204331 |
7 | 14243121662453452 |
oct | 1421757566234237 |
9 | 232212603072621 |
10 | 54011325135007 |
11 | 1623408aa6a269 |
12 | 608390b6096a7 |
13 | 241a327904616 |
14 | d4a23aa91499 |
15 | 639e59ed0857 |
hex | 311f7dd9389f |
54011325135007 has 2 divisors, whose sum is σ = 54011325135008. Its totient is φ = 54011325135006.
The previous prime is 54011325134971. The next prime is 54011325135029. The reversal of 54011325135007 is 70053152311045.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54011325135007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54011325135307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27005662567503 + 27005662567504.
It is an arithmetic number, because the mean of its divisors is an integer number (27005662567504).
Almost surely, 254011325135007 is an apocalyptic number.
54011325135007 is a deficient number, since it is larger than the sum of its proper divisors (1).
54011325135007 is an equidigital number, since it uses as much as digits as its factorization.
54011325135007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 37.
The spelling of 54011325135007 in words is "fifty-four trillion, eleven billion, three hundred twenty-five million, one hundred thirty-five thousand, seven".
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