Base | Representation |
---|---|
bin | 100000001100100… |
… | …110101000101101 |
3 | 1101122102201122112 |
4 | 200030212220231 |
5 | 2101241044033 |
6 | 125333453405 |
7 | 16246260626 |
oct | 4014465055 |
9 | 1348381575 |
10 | 540174893 |
11 | 257a07435 |
12 | 130aa1265 |
13 | 87bb041b |
14 | 51a52a4d |
15 | 32651c48 |
hex | 20326a2d |
540174893 has 2 divisors, whose sum is σ = 540174894. Its totient is φ = 540174892.
The previous prime is 540174863. The next prime is 540174919. The reversal of 540174893 is 398471045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 377408329 + 162766564 = 19427^2 + 12758^2 .
It is a cyclic number.
It is not a de Polignac number, because 540174893 - 28 = 540174637 is a prime.
It is a super-2 number, since 2×5401748932 = 583577830055122898, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 540174893.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540174863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270087446 + 270087447.
It is an arithmetic number, because the mean of its divisors is an integer number (270087447).
Almost surely, 2540174893 is an apocalyptic number.
It is an amenable number.
540174893 is a deficient number, since it is larger than the sum of its proper divisors (1).
540174893 is an equidigital number, since it uses as much as digits as its factorization.
540174893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 41.
The square root of 540174893 is about 23241.6628708017. The cubic root of 540174893 is about 814.4131889411.
The spelling of 540174893 in words is "five hundred forty million, one hundred seventy-four thousand, eight hundred ninety-three".
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