Base | Representation |
---|---|
bin | 11000100100001110100100… |
… | …11000100110000001011111 |
3 | 21002021101111121022010220212 |
4 | 30102013102120212001133 |
5 | 24040041142314004401 |
6 | 310521020303003035 |
7 | 14243625000026402 |
oct | 1422072230460137 |
9 | 232241447263825 |
10 | 54021333344351 |
11 | 1623835638105a |
12 | 608584329947b |
13 | 241b261207599 |
14 | d4a909d4dd39 |
15 | 63a343960dbb |
hex | 3121d262605f |
54021333344351 has 2 divisors, whose sum is σ = 54021333344352. Its totient is φ = 54021333344350.
The previous prime is 54021333344333. The next prime is 54021333344357. The reversal of 54021333344351 is 15344333312045.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54021333344351 is a prime.
It is a super-2 number, since 2×540213333443512 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54021333344299 and 54021333344308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54021333344357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27010666672175 + 27010666672176.
It is an arithmetic number, because the mean of its divisors is an integer number (27010666672176).
Almost surely, 254021333344351 is an apocalyptic number.
54021333344351 is a deficient number, since it is larger than the sum of its proper divisors (1).
54021333344351 is an equidigital number, since it uses as much as digits as its factorization.
54021333344351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 41.
Adding to 54021333344351 its reverse (15344333312045), we get a palindrome (69365666656396).
The spelling of 54021333344351 in words is "fifty-four trillion, twenty-one billion, three hundred thirty-three million, three hundred forty-four thousand, three hundred fifty-one".
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