Base | Representation |
---|---|
bin | 100111010011100111010… |
… | …0110101101000001101111 |
3 | 201010110010101220120112201 |
4 | 1032213032212231001233 |
5 | 1202002241434042341 |
6 | 15253431014442331 |
7 | 1065204355365523 |
oct | 116471646550157 |
9 | 21113111816481 |
10 | 5402240143471 |
11 | 17a30937a78a6 |
12 | 732ba73633a7 |
13 | 30257684ab92 |
14 | 149681275d83 |
15 | 957d0b16331 |
hex | 4e9ce9ad06f |
5402240143471 has 2 divisors, whose sum is σ = 5402240143472. Its totient is φ = 5402240143470.
The previous prime is 5402240143463. The next prime is 5402240143493. The reversal of 5402240143471 is 1743410422045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5402240143471 - 23 = 5402240143463 is a prime.
It is a super-3 number, since 3×54022401434713 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5402240143471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5402240144471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2701120071735 + 2701120071736.
It is an arithmetic number, because the mean of its divisors is an integer number (2701120071736).
Almost surely, 25402240143471 is an apocalyptic number.
5402240143471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5402240143471 is an equidigital number, since it uses as much as digits as its factorization.
5402240143471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 107520, while the sum is 37.
The spelling of 5402240143471 in words is "five trillion, four hundred two billion, two hundred forty million, one hundred forty-three thousand, four hundred seventy-one".
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