Base | Representation |
---|---|
bin | 11000100100010001110001… |
… | …10101100001100010110011 |
3 | 21002021112221101122021101011 |
4 | 30102020320311201202303 |
5 | 24040103202331013321 |
6 | 310521503024051351 |
7 | 14244015411061546 |
oct | 1422107065414263 |
9 | 232245841567334 |
10 | 54023052204211 |
11 | 162390586559a2 |
12 | 6086042a63b57 |
13 | 241b47635831c |
14 | d4aa3034485d |
15 | 63a3e47dcae1 |
hex | 312238d618b3 |
54023052204211 has 2 divisors, whose sum is σ = 54023052204212. Its totient is φ = 54023052204210.
The previous prime is 54023052204151. The next prime is 54023052204217. The reversal of 54023052204211 is 11240225032045.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54023052204211 - 215 = 54023052171443 is a prime.
It is a super-2 number, since 2×540230522042112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54023052204217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27011526102105 + 27011526102106.
It is an arithmetic number, because the mean of its divisors is an integer number (27011526102106).
Almost surely, 254023052204211 is an apocalyptic number.
54023052204211 is a deficient number, since it is larger than the sum of its proper divisors (1).
54023052204211 is an equidigital number, since it uses as much as digits as its factorization.
54023052204211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 54023052204211 its reverse (11240225032045), we get a palindrome (65263277236256).
The spelling of 54023052204211 in words is "fifty-four trillion, twenty-three billion, fifty-two million, two hundred four thousand, two hundred eleven".
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