Base | Representation |
---|---|
bin | 110010010100100001… |
… | …011110111100111011 |
3 | 12011110112122011200100 |
4 | 302110201132330323 |
5 | 1341124020204201 |
6 | 40453252410443 |
7 | 3621643301400 |
oct | 622441367473 |
9 | 164415564610 |
10 | 54031413051 |
11 | 20a07362380 |
12 | a57b016a23 |
13 | 513103c635 |
14 | 2887d002a7 |
15 | 1613772886 |
hex | c9485ef3b |
54031413051 has 72 divisors (see below), whose sum is σ = 101148562944. Its totient is φ = 27470953440.
The previous prime is 54031413049. The next prime is 54031413053. The reversal of 54031413051 is 15031413045.
It is a happy number.
54031413051 is a `hidden beast` number, since 5 + 40 + 314 + 1 + 305 + 1 = 666.
It is an interprime number because it is at equal distance from previous prime (54031413049) and next prime (54031413053).
It is not a de Polignac number, because 54031413051 - 21 = 54031413049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (54031413053) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 109506 + ... + 346488.
It is an arithmetic number, because the mean of its divisors is an integer number (1404841152).
Almost surely, 254031413051 is an apocalyptic number.
54031413051 is a deficient number, since it is larger than the sum of its proper divisors (47117149893).
54031413051 is a wasteful number, since it uses less digits than its factorization.
54031413051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237061 (or 237051 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 54031413051 its reverse (15031413045), we get a palindrome (69062826096).
The spelling of 54031413051 in words is "fifty-four billion, thirty-one million, four hundred thirteen thousand, fifty-one".
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