Base | Representation |
---|---|
bin | 111101011011011111011000… |
… | …0010001001100001011101111 |
3 | 2121212011222202020012021100111 |
4 | 1322312332300101030023233 |
5 | 1031310412112410413424 |
6 | 5153112421000040451 |
7 | 221546161430523112 |
oct | 17266766021141357 |
9 | 2555158666167314 |
10 | 540339907904239 |
11 | 14719496041a283 |
12 | 507295b1a63127 |
13 | 1a266ab0a35771 |
14 | 976083bd10579 |
15 | 427073366d194 |
hex | 1eb6fb044c2ef |
540339907904239 has 2 divisors, whose sum is σ = 540339907904240. Its totient is φ = 540339907904238.
The previous prime is 540339907904227. The next prime is 540339907904257. The reversal of 540339907904239 is 932409709933045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540339907904239 - 25 = 540339907904207 is a prime.
It is a super-3 number, since 3×5403399079042393 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540339907904299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270169953952119 + 270169953952120.
It is an arithmetic number, because the mean of its divisors is an integer number (270169953952120).
Almost surely, 2540339907904239 is an apocalyptic number.
540339907904239 is a deficient number, since it is larger than the sum of its proper divisors (1).
540339907904239 is an equidigital number, since it uses as much as digits as its factorization.
540339907904239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 198404640, while the sum is 67.
The spelling of 540339907904239 in words is "five hundred forty trillion, three hundred thirty-nine billion, nine hundred seven million, nine hundred four thousand, two hundred thirty-nine".
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