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540344113 is a prime number
BaseRepresentation
bin100000001101001…
…111111100110001
31101122202022202221
4200031033330301
52101312002423
6125341241041
716250564161
oct4015177461
91348668687
10540344113
11258012591
12130b63181
1387c3c45a
1451a985a1
1532686e5d
hex2034ff31

540344113 has 2 divisors, whose sum is σ = 540344114. Its totient is φ = 540344112.

The previous prime is 540344081. The next prime is 540344117. The reversal of 540344113 is 311443045.

540344113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 511528689 + 28815424 = 22617^2 + 5368^2 .

It is a cyclic number.

It is not a de Polignac number, because 540344113 - 25 = 540344081 is a prime.

It is not a weakly prime, because it can be changed into another prime (540344117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270172056 + 270172057.

It is an arithmetic number, because the mean of its divisors is an integer number (270172057).

Almost surely, 2540344113 is an apocalyptic number.

It is an amenable number.

540344113 is a deficient number, since it is larger than the sum of its proper divisors (1).

540344113 is an equidigital number, since it uses as much as digits as its factorization.

540344113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 540344113 is about 23245.3030309351. The cubic root of 540344113 is about 814.4982235061.

Adding to 540344113 its reverse (311443045), we get a palindrome (851787158).

The spelling of 540344113 in words is "five hundred forty million, three hundred forty-four thousand, one hundred thirteen".