Base | Representation |
---|---|
bin | 111101011100000001100111… |
… | …0100111010001100101100011 |
3 | 2121212110000112012201120212222 |
4 | 1322320003032213101211203 |
5 | 1031313113201423012201 |
6 | 5153210300400541255 |
7 | 221554403421424541 |
oct | 17270031647214543 |
9 | 2555400465646788 |
10 | 540413431454051 |
11 | 14721305a563491 |
12 | 5073b8b092182b |
13 | 1a2709ca17381c |
14 | 9764214894d91 |
15 | 42725d828d91b |
hex | 1eb80ce9d1963 |
540413431454051 has 2 divisors, whose sum is σ = 540413431454052. Its totient is φ = 540413431454050.
The previous prime is 540413431454047. The next prime is 540413431454063. The reversal of 540413431454051 is 150454134314045.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540413431454051 - 22 = 540413431454047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 540413431453993 and 540413431454011.
It is not a weakly prime, because it can be changed into another prime (540413431454251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270206715727025 + 270206715727026.
It is an arithmetic number, because the mean of its divisors is an integer number (270206715727026).
Almost surely, 2540413431454051 is an apocalyptic number.
540413431454051 is a deficient number, since it is larger than the sum of its proper divisors (1).
540413431454051 is an equidigital number, since it uses as much as digits as its factorization.
540413431454051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152000, while the sum is 44.
Adding to 540413431454051 its reverse (150454134314045), we get a palindrome (690867565768096).
The spelling of 540413431454051 in words is "five hundred forty trillion, four hundred thirteen billion, four hundred thirty-one million, four hundred fifty-four thousand, fifty-one".
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