Search a number
-
+
540433100041 is a prime number
BaseRepresentation
bin1111101110101000101…
…00101010110100001001
31220122221201020000022021
413313110110222310021
532323301333200131
61052134352524441
754021302361442
oct7672424526411
91818851200267
10540433100041
11199218439a5a
12888a5b50721
133bc68b60943
141c22b1302c9
15e0d066ae11
hex7dd452ad09

540433100041 has 2 divisors, whose sum is σ = 540433100042. Its totient is φ = 540433100040.

The previous prime is 540433100029. The next prime is 540433100057. The reversal of 540433100041 is 140001334045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 540401414400 + 31685641 = 735120^2 + 5629^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-540433100041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 540433099979 and 540433100015.

It is not a weakly prime, because it can be changed into another prime (540433100941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270216550020 + 270216550021.

It is an arithmetic number, because the mean of its divisors is an integer number (270216550021).

Almost surely, 2540433100041 is an apocalyptic number.

It is an amenable number.

540433100041 is a deficient number, since it is larger than the sum of its proper divisors (1).

540433100041 is an equidigital number, since it uses as much as digits as its factorization.

540433100041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 540433100041 its reverse (140001334045), we get a palindrome (680434434086).

The spelling of 540433100041 in words is "five hundred forty billion, four hundred thirty-three million, one hundred thousand, forty-one".