Base | Representation |
---|---|
bin | 1111101110101000101… |
… | …00101010110100001001 |
3 | 1220122221201020000022021 |
4 | 13313110110222310021 |
5 | 32323301333200131 |
6 | 1052134352524441 |
7 | 54021302361442 |
oct | 7672424526411 |
9 | 1818851200267 |
10 | 540433100041 |
11 | 199218439a5a |
12 | 888a5b50721 |
13 | 3bc68b60943 |
14 | 1c22b1302c9 |
15 | e0d066ae11 |
hex | 7dd452ad09 |
540433100041 has 2 divisors, whose sum is σ = 540433100042. Its totient is φ = 540433100040.
The previous prime is 540433100029. The next prime is 540433100057. The reversal of 540433100041 is 140001334045.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 540401414400 + 31685641 = 735120^2 + 5629^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-540433100041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 540433099979 and 540433100015.
It is not a weakly prime, because it can be changed into another prime (540433100941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270216550020 + 270216550021.
It is an arithmetic number, because the mean of its divisors is an integer number (270216550021).
Almost surely, 2540433100041 is an apocalyptic number.
It is an amenable number.
540433100041 is a deficient number, since it is larger than the sum of its proper divisors (1).
540433100041 is an equidigital number, since it uses as much as digits as its factorization.
540433100041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 540433100041 its reverse (140001334045), we get a palindrome (680434434086).
The spelling of 540433100041 in words is "five hundred forty billion, four hundred thirty-three million, one hundred thousand, forty-one".
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