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5404433 is a prime number
BaseRepresentation
bin10100100111011100010001
3101011120111012
4110213130101
52340420213
6311500305
763636236
oct24473421
911146435
105404433
113061481
121987695
131172bb8
14a0978d
1571b4a8
hex527711

5404433 has 2 divisors, whose sum is σ = 5404434. Its totient is φ = 5404432.

The previous prime is 5404403. The next prime is 5404439. The reversal of 5404433 is 3344045.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5071504 + 332929 = 2252^2 + 577^2 .

It is a cyclic number.

It is not a de Polignac number, because 5404433 - 28 = 5404177 is a prime.

It is an Ulam number.

It is a junction number, because it is equal to n+sod(n) for n = 5404399 and 5404408.

It is not a weakly prime, because it can be changed into another prime (5404439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2702216 + 2702217.

It is an arithmetic number, because the mean of its divisors is an integer number (2702217).

Almost surely, 25404433 is an apocalyptic number.

It is an amenable number.

5404433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5404433 is an equidigital number, since it uses as much as digits as its factorization.

5404433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 23.

The square root of 5404433 is about 2324.7436417807. The cubic root of 5404433 is about 175.4890592011.

Adding to 5404433 its reverse (3344045), we get a palindrome (8748478).

The spelling of 5404433 in words is "five million, four hundred four thousand, four hundred thirty-three".