Base | Representation |
---|---|
bin | 1111101110110000110… |
… | …11100010111010000011 |
3 | 1220200010111220002002101 |
4 | 13313120123202322003 |
5 | 32323422003332043 |
6 | 1052145253531231 |
7 | 54023100202525 |
oct | 7673033427203 |
9 | 1820114802071 |
10 | 540502011523 |
11 | 1992533271a1 |
12 | 88905043b17 |
13 | 3bc7a20ab76 |
14 | 1c23634ba15 |
15 | e0d672e24d |
hex | 7dd86e2e83 |
540502011523 has 2 divisors, whose sum is σ = 540502011524. Its totient is φ = 540502011522.
The previous prime is 540502011487. The next prime is 540502011551. The reversal of 540502011523 is 325110205045.
It is an a-pointer prime, because the next prime (540502011551) can be obtained adding 540502011523 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 540502011523 - 29 = 540502011011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 540502011491 and 540502011500.
It is not a weakly prime, because it can be changed into another prime (540502011563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270251005761 + 270251005762.
It is an arithmetic number, because the mean of its divisors is an integer number (270251005762).
Almost surely, 2540502011523 is an apocalyptic number.
540502011523 is a deficient number, since it is larger than the sum of its proper divisors (1).
540502011523 is an equidigital number, since it uses as much as digits as its factorization.
540502011523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 28.
Adding to 540502011523 its reverse (325110205045), we get a palindrome (865612216568).
The spelling of 540502011523 in words is "five hundred forty billion, five hundred two million, eleven thousand, five hundred twenty-three".
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