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5405110054493 is a prime number
BaseRepresentation
bin100111010100111100110…
…1010100010111001011101
3201010201112102011011100112
41032221321222202321131
51202024131133220433
615255023454535405
71065335444260202
oct116517152427135
921121472134315
105405110054493
1117a4326795496
12733668507565
133029132b5296
14149874497ca9
15958eca60348
hex4ea79aa2e5d

5405110054493 has 2 divisors, whose sum is σ = 5405110054494. Its totient is φ = 5405110054492.

The previous prime is 5405110054481. The next prime is 5405110054559. The reversal of 5405110054493 is 3944500115045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3102540528409 + 2302569526084 = 1761403^2 + 1517422^2 .

It is a cyclic number.

It is not a de Polignac number, because 5405110054493 - 212 = 5405110050397 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5405110054493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5405110054423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2702555027246 + 2702555027247.

It is an arithmetic number, because the mean of its divisors is an integer number (2702555027247).

Almost surely, 25405110054493 is an apocalyptic number.

It is an amenable number.

5405110054493 is a deficient number, since it is larger than the sum of its proper divisors (1).

5405110054493 is an equidigital number, since it uses as much as digits as its factorization.

5405110054493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 5405110054493 in words is "five trillion, four hundred five billion, one hundred ten million, fifty-four thousand, four hundred ninety-three".