Base | Representation |
---|---|
bin | 1111101110110101100… |
… | …00110100111101110111 |
3 | 1220200020020112021001121 |
4 | 13313122300310331313 |
5 | 32324012013114301 |
6 | 1052153212404411 |
7 | 54024053631253 |
oct | 7673260647567 |
9 | 1820206467047 |
10 | 540541144951 |
11 | 199273425775 |
12 | 88916176707 |
13 | 3bc85360142 |
14 | 1c23b617263 |
15 | e0d9dae3a1 |
hex | 7ddac34f77 |
540541144951 has 2 divisors, whose sum is σ = 540541144952. Its totient is φ = 540541144950.
The previous prime is 540541144919. The next prime is 540541144991. The reversal of 540541144951 is 159441145045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 540541144951 - 25 = 540541144919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 540541144898 and 540541144907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540541144901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270270572475 + 270270572476.
It is an arithmetic number, because the mean of its divisors is an integer number (270270572476).
Almost surely, 2540541144951 is an apocalyptic number.
540541144951 is a deficient number, since it is larger than the sum of its proper divisors (1).
540541144951 is an equidigital number, since it uses as much as digits as its factorization.
540541144951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 43.
Adding to 540541144951 its reverse (159441145045), we get a palindrome (699982289996).
The spelling of 540541144951 in words is "five hundred forty billion, five hundred forty-one million, one hundred forty-four thousand, nine hundred fifty-one".
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