Base | Representation |
---|---|
bin | 1010000100101110… |
… | …10001010000001101 |
3 | 111221220210100000111 |
4 | 11002113101100031 |
5 | 42034020113113 |
6 | 2252400000021 |
7 | 251011221466 |
oct | 50227212015 |
9 | 14856710014 |
10 | 5408363533 |
11 | 2325975631 |
12 | 106b300011 |
13 | 68263ac11 |
14 | 394401d6d |
15 | 219c1d13d |
hex | 1425d140d |
5408363533 has 2 divisors, whose sum is σ = 5408363534. Its totient is φ = 5408363532.
The previous prime is 5408363501. The next prime is 5408363539. The reversal of 5408363533 is 3353638045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5309599689 + 98763844 = 72867^2 + 9938^2 .
It is a cyclic number.
It is not a de Polignac number, because 5408363533 - 25 = 5408363501 is a prime.
It is a super-2 number, since 2×54083635332 = 58500792210168484178, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5408363539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2704181766 + 2704181767.
It is an arithmetic number, because the mean of its divisors is an integer number (2704181767).
Almost surely, 25408363533 is an apocalyptic number.
It is an amenable number.
5408363533 is a deficient number, since it is larger than the sum of its proper divisors (1).
5408363533 is an equidigital number, since it uses as much as digits as its factorization.
5408363533 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 40.
The square root of 5408363533 is about 73541.5769004174. The cubic root of 5408363533 is about 1755.3159208654.
The spelling of 5408363533 in words is "five billion, four hundred eight million, three hundred sixty-three thousand, five hundred thirty-three".
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