Base | Representation |
---|---|
bin | 100000001111110… |
… | …000011001111101 |
3 | 1101200222201022201 |
4 | 200033300121331 |
5 | 2101444020331 |
6 | 125403311501 |
7 | 16256302246 |
oct | 4017603175 |
9 | 1350881281 |
10 | 541001341 |
11 | 258421351 |
12 | 13121b591 |
13 | 8810c64a |
14 | 51bc9ccd |
15 | 32766a61 |
hex | 203f067d |
541001341 has 2 divisors, whose sum is σ = 541001342. Its totient is φ = 541001340.
The previous prime is 541001323. The next prime is 541001347. The reversal of 541001341 is 143100145.
541001341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 483560100 + 57441241 = 21990^2 + 7579^2 .
It is a cyclic number.
It is not a de Polignac number, because 541001341 - 215 = 540968573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (541001347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270500670 + 270500671.
It is an arithmetic number, because the mean of its divisors is an integer number (270500671).
Almost surely, 2541001341 is an apocalyptic number.
It is an amenable number.
541001341 is a deficient number, since it is larger than the sum of its proper divisors (1).
541001341 is an equidigital number, since it uses as much as digits as its factorization.
541001341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 19.
The square root of 541001341 is about 23259.4355262547. The cubic root of 541001341 is about 814.8283181851.
Adding to 541001341 its reverse (143100145), we get a palindrome (684101486).
The spelling of 541001341 in words is "five hundred forty-one million, one thousand, three hundred forty-one".
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