Base | Representation |
---|---|
bin | 11000100110100001111010… |
… | …00100001000000001111111 |
3 | 21002112221200011102020012111 |
4 | 30103100331010020001333 |
5 | 24042340141213131223 |
6 | 311021221241314451 |
7 | 14252425103142412 |
oct | 1423207504100177 |
9 | 232487604366174 |
10 | 54100432552063 |
11 | 162689568645a7 |
12 | 6099039495a27 |
13 | 24258588291c1 |
14 | d50691203b79 |
15 | 63c422ce830d |
hex | 31343d10807f |
54100432552063 has 2 divisors, whose sum is σ = 54100432552064. Its totient is φ = 54100432552062.
The previous prime is 54100432552057. The next prime is 54100432552141. The reversal of 54100432552063 is 36025523400145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54100432552063 - 221 = 54100430454911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54100432552963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27050216276031 + 27050216276032.
It is an arithmetic number, because the mean of its divisors is an integer number (27050216276032).
Almost surely, 254100432552063 is an apocalyptic number.
54100432552063 is a deficient number, since it is larger than the sum of its proper divisors (1).
54100432552063 is an equidigital number, since it uses as much as digits as its factorization.
54100432552063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 54100432552063 in words is "fifty-four trillion, one hundred billion, four hundred thirty-two million, five hundred fifty-two thousand, sixty-three".
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