Base | Representation |
---|---|
bin | 100111010111010000010… |
… | …0101101010100111111111 |
3 | 201011012022020200120211211 |
4 | 1032232200211222213333 |
5 | 1202114244330213033 |
6 | 15301202451425251 |
7 | 1065602165466151 |
oct | 116564045524777 |
9 | 21135266616754 |
10 | 5410058054143 |
11 | 17a64358058a6 |
12 | 7346095b5227 |
13 | 303221438122 |
14 | 149bc36a0ad1 |
15 | 95adc1442cd |
hex | 4eba096a9ff |
5410058054143 has 2 divisors, whose sum is σ = 5410058054144. Its totient is φ = 5410058054142.
The previous prime is 5410058054111. The next prime is 5410058054161. The reversal of 5410058054143 is 3414508500145.
5410058054143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5410058054143 - 25 = 5410058054111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5410058054096 and 5410058054105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5410058024143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705029027071 + 2705029027072.
It is an arithmetic number, because the mean of its divisors is an integer number (2705029027072).
Almost surely, 25410058054143 is an apocalyptic number.
5410058054143 is a deficient number, since it is larger than the sum of its proper divisors (1).
5410058054143 is an equidigital number, since it uses as much as digits as its factorization.
5410058054143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192000, while the sum is 40.
The spelling of 5410058054143 in words is "five trillion, four hundred ten billion, fifty-eight million, fifty-four thousand, one hundred forty-three".
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