Base | Representation |
---|---|
bin | 11000100110100111011110… |
… | …10001100000011100110001 |
3 | 21002120020101112100110120021 |
4 | 30103103233101200130301 |
5 | 24042412302113420101 |
6 | 311022434044243441 |
7 | 14252562146362156 |
oct | 1423235721403461 |
9 | 232506345313507 |
10 | 54103422404401 |
11 | 1626a150523947 |
12 | 6099732840581 |
13 | 2425c140998b6 |
14 | d5089632822d |
15 | 63c54a5355a1 |
hex | 3134ef460731 |
54103422404401 has 2 divisors, whose sum is σ = 54103422404402. Its totient is φ = 54103422404400.
The previous prime is 54103422404393. The next prime is 54103422404531. The reversal of 54103422404401 is 10440422430145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34102983730176 + 20000438674225 = 5839776^2 + 4472185^2 .
It is a cyclic number.
It is not a de Polignac number, because 54103422404401 - 23 = 54103422404393 is a prime.
It is not a weakly prime, because it can be changed into another prime (54103422408401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27051711202200 + 27051711202201.
It is an arithmetic number, because the mean of its divisors is an integer number (27051711202201).
Almost surely, 254103422404401 is an apocalyptic number.
It is an amenable number.
54103422404401 is a deficient number, since it is larger than the sum of its proper divisors (1).
54103422404401 is an equidigital number, since it uses as much as digits as its factorization.
54103422404401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61440, while the sum is 34.
Adding to 54103422404401 its reverse (10440422430145), we get a palindrome (64543844834546).
The spelling of 54103422404401 in words is "fifty-four trillion, one hundred three billion, four hundred twenty-two million, four hundred four thousand, four hundred one".
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