Base | Representation |
---|---|
bin | 100111010111110000011… |
… | …0011011100101001000111 |
3 | 201011022002022220212110212 |
4 | 1032233200303130221013 |
5 | 1202124001131034321 |
6 | 15301501415110035 |
7 | 1065640660034444 |
oct | 116574063345107 |
9 | 21138068825425 |
10 | 5411135408711 |
11 | 17a693896327a |
12 | 73486a37231b |
13 | 3033636ba536 |
14 | 149c867c69cb |
15 | 95b51a0555b |
hex | 4ebe0cdca47 |
5411135408711 has 2 divisors, whose sum is σ = 5411135408712. Its totient is φ = 5411135408710.
The previous prime is 5411135408629. The next prime is 5411135408719. The reversal of 5411135408711 is 1178045311145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5411135408711 - 222 = 5411131214407 is a prime.
It is a super-2 number, since 2×54111354087112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5411135408719) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705567704355 + 2705567704356.
It is an arithmetic number, because the mean of its divisors is an integer number (2705567704356).
Almost surely, 25411135408711 is an apocalyptic number.
5411135408711 is a deficient number, since it is larger than the sum of its proper divisors (1).
5411135408711 is an equidigital number, since it uses as much as digits as its factorization.
5411135408711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 41.
The spelling of 5411135408711 in words is "five trillion, four hundred eleven billion, one hundred thirty-five million, four hundred eight thousand, seven hundred eleven".
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