Base | Representation |
---|---|
bin | 100111010111110011100… |
… | …1010111001110111001001 |
3 | 201011022100202220111101121 |
4 | 1032233213022321313021 |
5 | 1202124211002033001 |
6 | 15301520152315241 |
7 | 1065643424651521 |
oct | 116574712716711 |
9 | 21138322814347 |
10 | 5411242221001 |
11 | 17a69931879a1 |
12 | 73489a0a2b21 |
13 | 30337c877986 |
14 | 149c96a6c681 |
15 | 95b5b0a36a1 |
hex | 4ebe72b9dc9 |
5411242221001 has 2 divisors, whose sum is σ = 5411242221002. Its totient is φ = 5411242221000.
The previous prime is 5411242220911. The next prime is 5411242221089. The reversal of 5411242221001 is 1001222421145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4435977342976 + 975264878025 = 2106176^2 + 987555^2 .
It is a cyclic number.
It is not a de Polignac number, because 5411242221001 - 211 = 5411242218953 is a prime.
It is not a weakly prime, because it can be changed into another prime (5411242221901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705621110500 + 2705621110501.
It is an arithmetic number, because the mean of its divisors is an integer number (2705621110501).
Almost surely, 25411242221001 is an apocalyptic number.
It is an amenable number.
5411242221001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5411242221001 is an equidigital number, since it uses as much as digits as its factorization.
5411242221001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 5411242221001 its reverse (1001222421145), we get a palindrome (6412464642146).
The spelling of 5411242221001 in words is "five trillion, four hundred eleven billion, two hundred forty-two million, two hundred twenty-one thousand, one".
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