Base | Representation |
---|---|
bin | 11000100110111011100110… |
… | …11110000111110111101100 |
3 | 21002121021021202012100000111 |
4 | 30103131303132013313230 |
5 | 24043101420420114300 |
6 | 311031422325505404 |
7 | 14253424033430152 |
oct | 1423356336076754 |
9 | 232537252170014 |
10 | 54114230238700 |
11 | 1627379723a805 |
12 | 609b84a272264 |
13 | 2426c47250b18 |
14 | d511dd8953d2 |
15 | 63c97e2b69ba |
hex | 313773787dec |
54114230238700 has 72 divisors (see below), whose sum is σ = 117649270242560. Its totient is φ = 21604907174400.
The previous prime is 54114230238647. The next prime is 54114230238701. The reversal of 54114230238700 is 783203241145.
54114230238700 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (54114230238701) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 179178421 + ... + 179480179.
Almost surely, 254114230238700 is an apocalyptic number.
54114230238700 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
54114230238700 is an abundant number, since it is smaller than the sum of its proper divisors (63535040003860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
54114230238700 is a wasteful number, since it uses less digits than its factorization.
54114230238700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305147 (or 305140 counting only the distinct ones).
The product of its (nonzero) digits is 161280, while the sum is 40.
Adding to 54114230238700 its reverse (783203241145), we get a palindrome (54897433479845).
The spelling of 54114230238700 in words is "fifty-four trillion, one hundred fourteen billion, two hundred thirty million, two hundred thirty-eight thousand, seven hundred".
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