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54121122432 = 2733132194877
BaseRepresentation
bin110010011001110111…
…101100101010000000
312011200210102212211000
4302121313230222000
51341320001404212
640510215252000
73624112643646
oct623167545200
9164623385730
1054121122432
1120a52a65363
12a5a507a000
1351467bc200
142895bb3196
15161b5931dc
hexc99deca80

54121122432 has 384 divisors, whose sum is σ = 182105496000. Its totient is φ = 15772962816.

The previous prime is 54121122403. The next prime is 54121122467. The reversal of 54121122432 is 23422112145.

54121122432 is a `hidden beast` number, since 5 + 412 + 1 + 1 + 2 + 243 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 54121122396 and 54121122405.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11094778 + ... + 11099654.

Almost surely, 254121122432 is an apocalyptic number.

54121122432 is a gapful number since it is divisible by the number (52) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 54121122432, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (91052748000).

54121122432 is an abundant number, since it is smaller than the sum of its proper divisors (127984373568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

54121122432 is a wasteful number, since it uses less digits than its factorization.

54121122432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4945 (or 4914 counting only the distinct ones).

The product of its digits is 3840, while the sum is 27.

Adding to 54121122432 its reverse (23422112145), we get a palindrome (77543234577).

It can be divided in two parts, 5412 and 1122432, that added together give a square (1127844 = 10622).

The spelling of 54121122432 in words is "fifty-four billion, one hundred twenty-one million, one hundred twenty-two thousand, four hundred thirty-two".