Base | Representation |
---|---|
bin | 100111011000001110011… |
… | …0111100001110111110111 |
3 | 201011101200120002111001201 |
4 | 1032300130313201313313 |
5 | 1202133032114033141 |
6 | 15302145413433331 |
7 | 1066004644260112 |
oct | 116603467416767 |
9 | 21141616074051 |
10 | 5412143111671 |
11 | 17a730576843a |
12 | 734aab93b847 |
13 | 3034943c388a |
14 | 149d4057b579 |
15 | 95bb0209031 |
hex | 4ec1cde1df7 |
5412143111671 has 2 divisors, whose sum is σ = 5412143111672. Its totient is φ = 5412143111670.
The previous prime is 5412143111659. The next prime is 5412143111693. The reversal of 5412143111671 is 1761113412145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5412143111671 - 211 = 5412143109623 is a prime.
It is a super-2 number, since 2×54121431116712 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5412143111671.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5412143111471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2706071555835 + 2706071555836.
It is an arithmetic number, because the mean of its divisors is an integer number (2706071555836).
Almost surely, 25412143111671 is an apocalyptic number.
5412143111671 is a deficient number, since it is larger than the sum of its proper divisors (1).
5412143111671 is an equidigital number, since it uses as much as digits as its factorization.
5412143111671 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 37.
The spelling of 5412143111671 in words is "five trillion, four hundred twelve billion, one hundred forty-three million, one hundred eleven thousand, six hundred seventy-one".
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