Base | Representation |
---|---|
bin | 11000100111001010000101… |
… | …10010100101000010111101 |
3 | 21002122000100110212111011211 |
4 | 30103211002302211002331 |
5 | 24043213330340431333 |
6 | 311035145524444421 |
7 | 14254120461566653 |
oct | 1423450262450275 |
9 | 232560313774154 |
10 | 54122003452093 |
11 | 16277015a9a005 |
12 | 60a1259549711 |
13 | 24278b57bb485 |
14 | d51739da6dd3 |
15 | 63cc86915ecd |
hex | 313942ca50bd |
54122003452093 has 2 divisors, whose sum is σ = 54122003452094. Its totient is φ = 54122003452092.
The previous prime is 54122003452087. The next prime is 54122003452189. The reversal of 54122003452093 is 39025430022145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49993129818724 + 4128873633369 = 7070582^2 + 2031963^2 .
It is a cyclic number.
It is not a de Polignac number, because 54122003452093 - 25 = 54122003452061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54122003452043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27061001726046 + 27061001726047.
It is an arithmetic number, because the mean of its divisors is an integer number (27061001726047).
Almost surely, 254122003452093 is an apocalyptic number.
It is an amenable number.
54122003452093 is a deficient number, since it is larger than the sum of its proper divisors (1).
54122003452093 is an equidigital number, since it uses as much as digits as its factorization.
54122003452093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 54122003452093 in words is "fifty-four trillion, one hundred twenty-two billion, three million, four hundred fifty-two thousand, ninety-three".
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