Base | Representation |
---|---|
bin | 100111011000010001011… |
… | …1001111101110001101111 |
3 | 201011101221121201011010012 |
4 | 1032300202321331301233 |
5 | 1202133234032213201 |
6 | 15302203433003435 |
7 | 1066010314313633 |
oct | 116604271756157 |
9 | 21141847634105 |
10 | 5412244413551 |
11 | 17a7357968aa8 |
12 | 734b1985357b |
13 | 3034ac3a1b11 |
14 | 149d4dbcadc3 |
15 | 95bb90695bb |
hex | 4ec22e7dc6f |
5412244413551 has 2 divisors, whose sum is σ = 5412244413552. Its totient is φ = 5412244413550.
The previous prime is 5412244413529. The next prime is 5412244413559. The reversal of 5412244413551 is 1553144422145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5412244413551 - 214 = 5412244397167 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5412244413499 and 5412244413508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5412244413559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2706122206775 + 2706122206776.
It is an arithmetic number, because the mean of its divisors is an integer number (2706122206776).
Almost surely, 25412244413551 is an apocalyptic number.
5412244413551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5412244413551 is an equidigital number, since it uses as much as digits as its factorization.
5412244413551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 384000, while the sum is 41.
Adding to 5412244413551 its reverse (1553144422145), we get a palindrome (6965388835696).
The spelling of 5412244413551 in words is "five trillion, four hundred twelve billion, two hundred forty-four million, four hundred thirteen thousand, five hundred fifty-one".
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