Base | Representation |
---|---|
bin | 110010011010000100… |
… | …011010011001101101 |
3 | 12011201000201012222012 |
4 | 302122010122121231 |
5 | 1341321330034113 |
6 | 40510414531005 |
7 | 3624153165311 |
oct | 623204323155 |
9 | 164630635865 |
10 | 54124455533 |
11 | 20a54931595 |
12 | a5a6206a65 |
13 | 51473b8365 |
14 | 28963ddb41 |
15 | 161ba00aa8 |
hex | c9a11a66d |
54124455533 has 2 divisors, whose sum is σ = 54124455534. Its totient is φ = 54124455532.
The previous prime is 54124455529. The next prime is 54124455559. The reversal of 54124455533 is 33555442145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42200252329 + 11924203204 = 205427^2 + 109198^2 .
It is a cyclic number.
It is not a de Polignac number, because 54124455533 - 22 = 54124455529 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54124455233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27062227766 + 27062227767.
It is an arithmetic number, because the mean of its divisors is an integer number (27062227767).
Almost surely, 254124455533 is an apocalyptic number.
It is an amenable number.
54124455533 is a deficient number, since it is larger than the sum of its proper divisors (1).
54124455533 is an equidigital number, since it uses as much as digits as its factorization.
54124455533 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 720000, while the sum is 41.
Adding to 54124455533 its reverse (33555442145), we get a palindrome (87679897678).
The spelling of 54124455533 in words is "fifty-four billion, one hundred twenty-four million, four hundred fifty-five thousand, five hundred thirty-three".
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