Base | Representation |
---|---|
bin | 110010011010010010… |
… | …011000001001101101 |
3 | 12011201021121012122101 |
4 | 302122102120021231 |
5 | 1341323244210313 |
6 | 40511025215101 |
7 | 3624226253224 |
oct | 623222301155 |
9 | 164637535571 |
10 | 54128116333 |
11 | 20a56a01a45 |
12 | a5a7491491 |
13 | 514809a705 |
14 | 2896ab3cbb |
15 | 161bec55dd |
hex | c9a49826d |
54128116333 has 2 divisors, whose sum is σ = 54128116334. Its totient is φ = 54128116332.
The previous prime is 54128116283. The next prime is 54128116439. The reversal of 54128116333 is 33361182145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34240911849 + 19887204484 = 185043^2 + 141022^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54128116333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54128116292 and 54128116301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54128116733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27064058166 + 27064058167.
It is an arithmetic number, because the mean of its divisors is an integer number (27064058167).
Almost surely, 254128116333 is an apocalyptic number.
It is an amenable number.
54128116333 is a deficient number, since it is larger than the sum of its proper divisors (1).
54128116333 is an equidigital number, since it uses as much as digits as its factorization.
54128116333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 37.
Adding to 54128116333 its reverse (33361182145), we get a palindrome (87489298478).
The spelling of 54128116333 in words is "fifty-four billion, one hundred twenty-eight million, one hundred sixteen thousand, three hundred thirty-three".
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