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541300403004 = 22376435901919
BaseRepresentation
bin1111110000010000000…
…01001010101100111100
31220202012011012120022020
413320020001022230330
532332040400344004
61052400414120140
754051633336504
oct7701001125474
91822164176266
10541300403004
11199622a69569
1288aa84b0050
133c07674986a
141c2b03b8a04
15e1318898d9
hex7e0804ab3c

541300403004 has 24 divisors (see below), whose sum is σ = 1263199741440. Its totient is φ = 180409829424.

The previous prime is 541300402861. The next prime is 541300403029. The reversal of 541300403004 is 400304003145.

It is a super-2 number, since 2×5413004030042 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2859244 + ... + 3042675.

It is an arithmetic number, because the mean of its divisors is an integer number (52633322560).

Almost surely, 2541300403004 is an apocalyptic number.

It is an amenable number.

541300403004 is an abundant number, since it is smaller than the sum of its proper divisors (721899338436).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

541300403004 is a wasteful number, since it uses less digits than its factorization.

541300403004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5909569 (or 5909567 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 24.

Adding to 541300403004 its reverse (400304003145), we get a palindrome (941604406149).

The spelling of 541300403004 in words is "five hundred forty-one billion, three hundred million, four hundred three thousand, four".

Divisors: 1 2 3 4 6 12 7643 15286 22929 30572 45858 91716 5901919 11803838 17705757 23607676 35411514 70823028 45108366917 90216733834 135325100751 180433467668 270650201502 541300403004