Base | Representation |
---|---|
bin | 1111110000010010011… |
… | …00011000100001010011 |
3 | 1220202020112022022111021 |
4 | 13320021030120201103 |
5 | 32332110422323103 |
6 | 1052402400500311 |
7 | 54052263050566 |
oct | 7701114304123 |
9 | 1822215268437 |
10 | 541320120403 |
11 | 199633106537 |
12 | 88ab301a697 |
13 | 3c07a86146a |
14 | 1c2b2c6c4dd |
15 | e133481bbd |
hex | 7e09318853 |
541320120403 has 2 divisors, whose sum is σ = 541320120404. Its totient is φ = 541320120402.
The previous prime is 541320120311. The next prime is 541320120457. The reversal of 541320120403 is 304021023145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 541320120403 - 29 = 541320119891 is a prime.
It is not a weakly prime, because it can be changed into another prime (541320120703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270660060201 + 270660060202.
It is an arithmetic number, because the mean of its divisors is an integer number (270660060202).
Almost surely, 2541320120403 is an apocalyptic number.
541320120403 is a deficient number, since it is larger than the sum of its proper divisors (1).
541320120403 is an equidigital number, since it uses as much as digits as its factorization.
541320120403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 541320120403 its reverse (304021023145), we get a palindrome (845341143548).
The spelling of 541320120403 in words is "five hundred forty-one billion, three hundred twenty million, one hundred twenty thousand, four hundred three".
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