Base | Representation |
---|---|
bin | 110010011010101001… |
… | …100110010000101001 |
3 | 12011201201001110120112 |
4 | 302122221212100221 |
5 | 1341331324002213 |
6 | 40511403504105 |
7 | 3624332064662 |
oct | 623251462051 |
9 | 164651043515 |
10 | 54134203433 |
11 | 20a5a38a302 |
12 | a5a9528035 |
13 | 514941c24b |
14 | 289781a369 |
15 | 161c7c8ea8 |
hex | c9aa66429 |
54134203433 has 2 divisors, whose sum is σ = 54134203434. Its totient is φ = 54134203432.
The previous prime is 54134203373. The next prime is 54134203441. The reversal of 54134203433 is 33430243145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31297855744 + 22836347689 = 176912^2 + 151117^2 .
It is a cyclic number.
It is not a de Polignac number, because 54134203433 - 212 = 54134199337 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54134203433.
It is not a weakly prime, because it can be changed into another prime (54134203033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27067101716 + 27067101717.
It is an arithmetic number, because the mean of its divisors is an integer number (27067101717).
Almost surely, 254134203433 is an apocalyptic number.
It is an amenable number.
54134203433 is a deficient number, since it is larger than the sum of its proper divisors (1).
54134203433 is an equidigital number, since it uses as much as digits as its factorization.
54134203433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 32.
Adding to 54134203433 its reverse (33430243145), we get a palindrome (87564446578).
The spelling of 54134203433 in words is "fifty-four billion, one hundred thirty-four million, two hundred three thousand, four hundred thirty-three".
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