Base | Representation |
---|---|
bin | 11000100111100110111110… |
… | …01010110111010100101001 |
3 | 21002200111101021212121210112 |
4 | 30103303133022313110221 |
5 | 24043442111030402433 |
6 | 311050232450024105 |
7 | 14255210005023131 |
oct | 1423633712672451 |
9 | 232614337777715 |
10 | 54137511965993 |
11 | 16282654163045 |
12 | 60a4267278035 |
13 | 24291b77b0911 |
14 | d523ab95bac1 |
15 | 63d3931c6348 |
hex | 313cdf2b7529 |
54137511965993 has 2 divisors, whose sum is σ = 54137511965994. Its totient is φ = 54137511965992.
The previous prime is 54137511965983. The next prime is 54137511966011. The reversal of 54137511965993 is 39956911573145.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52064479287184 + 2073032678809 = 7215572^2 + 1439803^2 .
It is a cyclic number.
It is not a de Polignac number, because 54137511965993 - 222 = 54137507771689 is a prime.
It is not a weakly prime, because it can be changed into another prime (54137511965983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27068755982996 + 27068755982997.
It is an arithmetic number, because the mean of its divisors is an integer number (27068755982997).
Almost surely, 254137511965993 is an apocalyptic number.
It is an amenable number.
54137511965993 is a deficient number, since it is larger than the sum of its proper divisors (1).
54137511965993 is an equidigital number, since it uses as much as digits as its factorization.
54137511965993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 137781000, while the sum is 68.
The spelling of 54137511965993 in words is "fifty-four trillion, one hundred thirty-seven billion, five hundred eleven million, nine hundred sixty-five thousand, nine hundred ninety-three".
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