Base | Representation |
---|---|
bin | 1010000101011111… |
… | …11110101110100101 |
3 | 111222100222102210001 |
4 | 11002233332232211 |
5 | 42042144410003 |
6 | 2253150501301 |
7 | 251120251123 |
oct | 50257765645 |
9 | 14870872701 |
10 | 5414841253 |
11 | 232959a418 |
12 | 1071504831 |
13 | 683a984a3 |
14 | 39520a913 |
15 | 21a59c61d |
hex | 142bfeba5 |
5414841253 has 2 divisors, whose sum is σ = 5414841254. Its totient is φ = 5414841252.
The previous prime is 5414841221. The next prime is 5414841307. The reversal of 5414841253 is 3521484145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5332358529 + 82482724 = 73023^2 + 9082^2 .
It is a cyclic number.
It is not a de Polignac number, because 5414841253 - 25 = 5414841221 is a prime.
It is a super-2 number, since 2×54148412532 = 58641011590381220018, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5414847253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707420626 + 2707420627.
It is an arithmetic number, because the mean of its divisors is an integer number (2707420627).
Almost surely, 25414841253 is an apocalyptic number.
It is an amenable number.
5414841253 is a deficient number, since it is larger than the sum of its proper divisors (1).
5414841253 is an equidigital number, since it uses as much as digits as its factorization.
5414841253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 76800, while the sum is 37.
The square root of 5414841253 is about 73585.6049305841. The cubic root of 5414841253 is about 1756.0164351983.
The spelling of 5414841253 in words is "five billion, four hundred fourteen million, eight hundred forty-one thousand, two hundred fifty-three".
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