Search a number
-
+
541624136423053 is a prime number
BaseRepresentation
bin111101100100110101011001…
…0010000001101011010001101
32122000201202120022201110122211
41323021222302100031122031
51031442432212411014203
65155534405430110421
7222041024005031005
oct17311526220153215
92560652508643584
10541624136423053
1114763a5629981a2
12508b64774ab411
131a32ac245079c8
1497a6a68a11005
154293d47b8bc6d
hex1ec9ab240d68d

541624136423053 has 2 divisors, whose sum is σ = 541624136423054. Its totient is φ = 541624136423052.

The previous prime is 541624136423047. The next prime is 541624136423063. The reversal of 541624136423053 is 350324631426145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 503916160997929 + 37707975425124 = 22448077^2 + 6140682^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-541624136423053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 541624136422988 and 541624136423006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541624136423023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270812068211526 + 270812068211527.

It is an arithmetic number, because the mean of its divisors is an integer number (270812068211527).

Almost surely, 2541624136423053 is an apocalyptic number.

It is an amenable number.

541624136423053 is a deficient number, since it is larger than the sum of its proper divisors (1).

541624136423053 is an equidigital number, since it uses as much as digits as its factorization.

541624136423053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6220800, while the sum is 49.

Adding to 541624136423053 its reverse (350324631426145), we get a palindrome (891948767849198).

The spelling of 541624136423053 in words is "five hundred forty-one trillion, six hundred twenty-four billion, one hundred thirty-six million, four hundred twenty-three thousand, fifty-three".