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5417667113 is a prime number
BaseRepresentation
bin1010000101110101…
…10000101000101001
3111222120022000010112
411002322300220221
542043410321423
62253331224105
7251153260565
oct50272605051
914876260115
105417667113
11233014a541
121072448035
136845477b1
143957446a5
1521a959a78
hex142eb0a29

5417667113 has 2 divisors, whose sum is σ = 5417667114. Its totient is φ = 5417667112.

The previous prime is 5417667107. The next prime is 5417667131. The reversal of 5417667113 is 3117667145.

5417667113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (5417667131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3282487849 + 2135179264 = 57293^2 + 46208^2 .

It is a cyclic number.

It is not a de Polignac number, because 5417667113 - 232 = 1122699817 is a prime.

It is a super-2 number, since 2×54176671132 = 58702233894563509538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5417667173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2708833556 + 2708833557.

It is an arithmetic number, because the mean of its divisors is an integer number (2708833557).

Almost surely, 25417667113 is an apocalyptic number.

It is an amenable number.

5417667113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5417667113 is an equidigital number, since it uses as much as digits as its factorization.

5417667113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 105840, while the sum is 41.

The square root of 5417667113 is about 73604.8036000369. The cubic root of 5417667113 is about 1756.3218546556.

The spelling of 5417667113 in words is "five billion, four hundred seventeen million, six hundred sixty-seven thousand, one hundred thirteen".