Base | Representation |
---|---|
bin | 1010000101110101… |
… | …10000101000111011 |
3 | 111222120022000011012 |
4 | 11002322300220323 |
5 | 42043410322011 |
6 | 2253331224135 |
7 | 251153260622 |
oct | 50272605073 |
9 | 14876260135 |
10 | 5417667131 |
11 | 233014a558 |
12 | 107244804b |
13 | 6845477c6 |
14 | 3957446b9 |
15 | 21a959a8b |
hex | 142eb0a3b |
5417667131 has 2 divisors, whose sum is σ = 5417667132. Its totient is φ = 5417667130.
The previous prime is 5417667113. The next prime is 5417667173. The reversal of 5417667131 is 1317667145.
5417667131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
Together with previous prime (5417667113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5417667131 - 226 = 5350558267 is a prime.
It is a super-2 number, since 2×54176671312 = 58702234284635542322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5417663131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2708833565 + 2708833566.
It is an arithmetic number, because the mean of its divisors is an integer number (2708833566).
Almost surely, 25417667131 is an apocalyptic number.
5417667131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5417667131 is an equidigital number, since it uses as much as digits as its factorization.
5417667131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 105840, while the sum is 41.
The square root of 5417667131 is about 73604.8037223115. The cubic root of 5417667131 is about 1756.3218566007.
The spelling of 5417667131 in words is "five billion, four hundred seventeen million, six hundred sixty-seven thousand, one hundred thirty-one".
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