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542013321503657 is a prime number
BaseRepresentation
bin111101100111101010100111…
…1011111011110001110101001
32122002002222010022010000021102
41323033111033133132032221
51032020321240301104112
65200433252113051145
7222111112245444533
oct17317251737361651
92562088108100242
10542013321503657
1114777a616804583
1250959990856ab5
131a358838380c53
1497bb828720853
15429e024da4bc2
hex1ecf54f7de3a9

542013321503657 has 2 divisors, whose sum is σ = 542013321503658. Its totient is φ = 542013321503656.

The previous prime is 542013321503509. The next prime is 542013321503671. The reversal of 542013321503657 is 756305123310245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 423605386968976 + 118407934534681 = 20581676^2 + 10881541^2 .

It is a cyclic number.

It is not a de Polignac number, because 542013321503657 - 214 = 542013321487273 is a prime.

It is not a weakly prime, because it can be changed into another prime (542013321503257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271006660751828 + 271006660751829.

It is an arithmetic number, because the mean of its divisors is an integer number (271006660751829).

Almost surely, 2542013321503657 is an apocalyptic number.

It is an amenable number.

542013321503657 is a deficient number, since it is larger than the sum of its proper divisors (1).

542013321503657 is an equidigital number, since it uses as much as digits as its factorization.

542013321503657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268000, while the sum is 47.

The spelling of 542013321503657 in words is "five hundred forty-two trillion, thirteen billion, three hundred twenty-one million, five hundred three thousand, six hundred fifty-seven".