Base | Representation |
---|---|
bin | 1111110001101000101… |
… | …00011010000100001101 |
3 | 1220211002221202010111221 |
4 | 13320310110122010031 |
5 | 32340101133103143 |
6 | 1053002244243341 |
7 | 54106226645413 |
oct | 7706424320415 |
9 | 1824087663457 |
10 | 542043644173 |
11 | 199974562669 |
12 | 890753a0551 |
13 | 3c164718b35 |
14 | 1c340dab2b3 |
15 | e176c4e2ed |
hex | 7e3451a10d |
542043644173 has 2 divisors, whose sum is σ = 542043644174. Its totient is φ = 542043644172.
The previous prime is 542043644161. The next prime is 542043644183. The reversal of 542043644173 is 371446340245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 431382299209 + 110661344964 = 656797^2 + 332658^2 .
It is a cyclic number.
It is not a de Polignac number, because 542043644173 - 25 = 542043644141 is a prime.
It is a super-2 number, since 2×5420436441732 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (542043644113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271021822086 + 271021822087.
It is an arithmetic number, because the mean of its divisors is an integer number (271021822087).
Almost surely, 2542043644173 is an apocalyptic number.
It is an amenable number.
542043644173 is a deficient number, since it is larger than the sum of its proper divisors (1).
542043644173 is an equidigital number, since it uses as much as digits as its factorization.
542043644173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 967680, while the sum is 43.
The spelling of 542043644173 in words is "five hundred forty-two billion, forty-three million, six hundred forty-four thousand, one hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •