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542046191873 is a prime number
BaseRepresentation
bin1111110001101000111…
…10001000000100000001
31220211010010112120022012
413320310132020010001
532340102311114443
61053002415022305
754106260416204
oct7706436100401
91824103476265
10542046191873
11199975a427aa
128907620a995
133c1650cb654
141c34147193b
15e1770a4118
hex7e34788101

542046191873 has 2 divisors, whose sum is σ = 542046191874. Its totient is φ = 542046191872.

The previous prime is 542046191783. The next prime is 542046191903. The reversal of 542046191873 is 378191640245.

It is a happy number.

Together with previous prime (542046191783) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 510686032129 + 31360159744 = 714623^2 + 177088^2 .

It is a cyclic number.

It is not a de Polignac number, because 542046191873 - 216 = 542046126337 is a prime.

It is a super-2 number, since 2×5420461918732 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (542046193873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271023095936 + 271023095937.

It is an arithmetic number, because the mean of its divisors is an integer number (271023095937).

It is a 1-persistent number, because it is pandigital, but 2⋅542046191873 = 1084092383746 is not.

Almost surely, 2542046191873 is an apocalyptic number.

It is an amenable number.

542046191873 is a deficient number, since it is larger than the sum of its proper divisors (1).

542046191873 is an equidigital number, since it uses as much as digits as its factorization.

542046191873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 542046191873 in words is "five hundred forty-two billion, forty-six million, one hundred ninety-one thousand, eight hundred seventy-three".