Base | Representation |
---|---|
bin | 11000101001110010110111… |
… | …01000000101001010001101 |
3 | 21002221200020022102210011111 |
4 | 30110321123220011022031 |
5 | 24101204413244144121 |
6 | 311144533052452021 |
7 | 14263506060402022 |
oct | 1424713350051215 |
9 | 232850208383144 |
10 | 54212614443661 |
11 | 16301493596103 |
12 | 60b6926a7a011 |
13 | 24332c608730b |
14 | d55c940ad549 |
15 | 6402db7322e1 |
hex | 314e5ba0528d |
54212614443661 has 2 divisors, whose sum is σ = 54212614443662. Its totient is φ = 54212614443660.
The previous prime is 54212614443563. The next prime is 54212614443671. The reversal of 54212614443661 is 16634441621245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53753736909636 + 458877534025 = 7331694^2 + 677405^2 .
It is a cyclic number.
It is not a de Polignac number, because 54212614443661 - 29 = 54212614443149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54212614443671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27106307221830 + 27106307221831.
It is an arithmetic number, because the mean of its divisors is an integer number (27106307221831).
Almost surely, 254212614443661 is an apocalyptic number.
It is an amenable number.
54212614443661 is a deficient number, since it is larger than the sum of its proper divisors (1).
54212614443661 is an equidigital number, since it uses as much as digits as its factorization.
54212614443661 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3317760, while the sum is 49.
The spelling of 54212614443661 in words is "fifty-four trillion, two hundred twelve billion, six hundred fourteen million, four hundred forty-three thousand, six hundred sixty-one".
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