Base | Representation |
---|---|
bin | 11000101010000101000110… |
… | …01000011110000010101001 |
3 | 21002222121111120022100222021 |
4 | 30111002203020132002221 |
5 | 24101334440414113423 |
6 | 311153232322024441 |
7 | 14264303501603434 |
oct | 1425024310360251 |
9 | 232877446270867 |
10 | 54222404051113 |
11 | 1630565756a081 |
12 | 60b87b94a8121 |
13 | 24341c62bc04c |
14 | d5654230681b |
15 | 6406b0dd195d |
hex | 3150a321e0a9 |
54222404051113 has 2 divisors, whose sum is σ = 54222404051114. Its totient is φ = 54222404051112.
The previous prime is 54222404051093. The next prime is 54222404051119. The reversal of 54222404051113 is 31115040422245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42336403129449 + 11886000921664 = 6506643^2 + 3447608^2 .
It is a cyclic number.
It is not a de Polignac number, because 54222404051113 - 213 = 54222404042921 is a prime.
It is not a weakly prime, because it can be changed into another prime (54222404051119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27111202025556 + 27111202025557.
It is an arithmetic number, because the mean of its divisors is an integer number (27111202025557).
Almost surely, 254222404051113 is an apocalyptic number.
It is an amenable number.
54222404051113 is a deficient number, since it is larger than the sum of its proper divisors (1).
54222404051113 is an equidigital number, since it uses as much as digits as its factorization.
54222404051113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 54222404051113 its reverse (31115040422245), we get a palindrome (85337444473358).
The spelling of 54222404051113 in words is "fifty-four trillion, two hundred twenty-two billion, four hundred four million, fifty-one thousand, one hundred thirteen".
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