Base | Representation |
---|---|
bin | 1111110001111110010… |
… | …00010001010110101101 |
3 | 1220211120121000120121002 |
4 | 13320333020101112231 |
5 | 32340434100342031 |
6 | 1053032243450045 |
7 | 54113561362121 |
oct | 7707710212655 |
9 | 1824517016532 |
10 | 542225012141 |
11 | 199a5797a04a |
12 | 89106086925 |
13 | 3c19317b567 |
14 | 1c35b0dd581 |
15 | e187b27ccb |
hex | 7e3f2115ad |
542225012141 has 2 divisors, whose sum is σ = 542225012142. Its totient is φ = 542225012140.
The previous prime is 542225012033. The next prime is 542225012149. The reversal of 542225012141 is 141210522245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 392013732100 + 150211280041 = 626110^2 + 387571^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-542225012141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (542225012149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271112506070 + 271112506071.
It is an arithmetic number, because the mean of its divisors is an integer number (271112506071).
Almost surely, 2542225012141 is an apocalyptic number.
It is an amenable number.
542225012141 is a deficient number, since it is larger than the sum of its proper divisors (1).
542225012141 is an equidigital number, since it uses as much as digits as its factorization.
542225012141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 542225012141 its reverse (141210522245), we get a palindrome (683435534386).
The spelling of 542225012141 in words is "five hundred forty-two billion, two hundred twenty-five million, twelve thousand, one hundred forty-one".
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