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542422146281 is a prime number
BaseRepresentation
bin1111110010010101110…
…00010001110011101001
31220212002022222000210112
413321022320101303221
532341340032140111
61053104005024105
754121504112201
oct7711270216351
91825068860715
10542422146281
1119a049184924
12891600b5035
133c1c4c71292
141c379377401
15e19a0b7e8b
hex7e4ae11ce9

542422146281 has 2 divisors, whose sum is σ = 542422146282. Its totient is φ = 542422146280.

The previous prime is 542422146251. The next prime is 542422146283. The reversal of 542422146281 is 182641224245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 507679050256 + 34743096025 = 712516^2 + 186395^2 .

It is a cyclic number.

It is not a de Polignac number, because 542422146281 - 210 = 542422145257 is a prime.

It is a super-2 number, since 2×5424221462812 (a number of 24 digits) contains 22 as substring.

Together with 542422146283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (542422146283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271211073140 + 271211073141.

It is an arithmetic number, because the mean of its divisors is an integer number (271211073141).

Almost surely, 2542422146281 is an apocalyptic number.

It is an amenable number.

542422146281 is a deficient number, since it is larger than the sum of its proper divisors (1).

542422146281 is an equidigital number, since it uses as much as digits as its factorization.

542422146281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 245760, while the sum is 41.

The spelling of 542422146281 in words is "five hundred forty-two billion, four hundred twenty-two million, one hundred forty-six thousand, two hundred eighty-one".