Base | Representation |
---|---|
bin | 1111110010011000010… |
… | …01101111001001001111 |
3 | 1220212010211010220202010 |
4 | 13321030021233021033 |
5 | 32341411014000421 |
6 | 1053110050432303 |
7 | 54122153450232 |
oct | 7711411571117 |
9 | 1825124126663 |
10 | 542443500111 |
11 | 19a05a23a317 |
12 | 89167292693 |
13 | 3c1c9509996 |
14 | 1c37c135419 |
15 | e19bdd5076 |
hex | 7e4c26f24f |
542443500111 has 32 divisors (see below), whose sum is σ = 797777164800. Its totient is φ = 326427192320.
The previous prime is 542443500089. The next prime is 542443500127. The reversal of 542443500111 is 111005344245.
It is a cyclic number.
It is not a de Polignac number, because 542443500111 - 211 = 542443498063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (542443504111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2075091 + ... + 2321828.
It is an arithmetic number, because the mean of its divisors is an integer number (24930536400).
Almost surely, 2542443500111 is an apocalyptic number.
542443500111 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
542443500111 is a deficient number, since it is larger than the sum of its proper divisors (255333664689).
542443500111 is a wasteful number, since it uses less digits than its factorization.
542443500111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4397039.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 542443500111 its reverse (111005344245), we get a palindrome (653448844356).
The spelling of 542443500111 in words is "five hundred forty-two billion, four hundred forty-three million, five hundred thousand, one hundred eleven".
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