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5424533110081 is a prime number
BaseRepresentation
bin100111011101111111101…
…0111100111110101000001
3201012120200001001121122201
41032323333113213311001
51202333420434010311
615311555054233201
71066623662441341
oct116737727476501
921176601047581
105424533110081
111801593583648
127373891b5801
133046ba2a7497
1414a797cb8d21
1596187d149c1
hex4eeff5e7d41

5424533110081 has 2 divisors, whose sum is σ = 5424533110082. Its totient is φ = 5424533110080.

The previous prime is 5424533110079. The next prime is 5424533110091. The reversal of 5424533110081 is 1800113354245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5393843676225 + 30689433856 = 2322465^2 + 175184^2 .

It is a cyclic number.

It is not a de Polignac number, because 5424533110081 - 21 = 5424533110079 is a prime.

It is a super-2 number, since 2×54245331100812 (a number of 26 digits) contains 22 as substring.

Together with 5424533110079, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 5424533110081.

It is not a weakly prime, because it can be changed into another prime (5424533110091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2712266555040 + 2712266555041.

It is an arithmetic number, because the mean of its divisors is an integer number (2712266555041).

Almost surely, 25424533110081 is an apocalyptic number.

It is an amenable number.

5424533110081 is a deficient number, since it is larger than the sum of its proper divisors (1).

5424533110081 is an equidigital number, since it uses as much as digits as its factorization.

5424533110081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 5424533110081 in words is "five trillion, four hundred twenty-four billion, five hundred thirty-three million, one hundred ten thousand, eighty-one".