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54251550344081 is a prime number
BaseRepresentation
bin11000101010111011011000…
…11000110000001110010001
321010002101201211012110110102
430111131230120300032101
524102324133342002311
6311214452420142145
714266354664161466
oct1425355430601621
9233071654173412
1054251550344081
1116316a5391a402
126102392537955
132436b8c84874c
14d57b0920566d
15641319ac543b
hex31576c630391

54251550344081 has 2 divisors, whose sum is σ = 54251550344082. Its totient is φ = 54251550344080.

The previous prime is 54251550343999. The next prime is 54251550344141. The reversal of 54251550344081 is 18044305515245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44978818890625 + 9272731453456 = 6706625^2 + 3045116^2 .

It is a cyclic number.

It is not a de Polignac number, because 54251550344081 - 238 = 53976672437137 is a prime.

It is a super-3 number, since 3×542515503440813 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (54251550340081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27125775172040 + 27125775172041.

It is an arithmetic number, because the mean of its divisors is an integer number (27125775172041).

Almost surely, 254251550344081 is an apocalyptic number.

It is an amenable number.

54251550344081 is a deficient number, since it is larger than the sum of its proper divisors (1).

54251550344081 is an equidigital number, since it uses as much as digits as its factorization.

54251550344081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920000, while the sum is 47.

The spelling of 54251550344081 in words is "fifty-four trillion, two hundred fifty-one billion, five hundred fifty million, three hundred forty-four thousand, eighty-one".