Base | Representation |
---|---|
bin | 11000101010111110011010… |
… | …00001100010010011111011 |
3 | 21010002112220210222012222001 |
4 | 30111133031001202103323 |
5 | 24102340443420211424 |
6 | 311215321334241431 |
7 | 14266443112060351 |
oct | 1425371501422373 |
9 | 233075823865861 |
10 | 54253171647739 |
11 | 16317706021889 |
12 | 61027654b6277 |
13 | 243708a70011c |
14 | d57c206837d1 |
15 | 6413b20d1844 |
hex | 3157cd0624fb |
54253171647739 has 2 divisors, whose sum is σ = 54253171647740. Its totient is φ = 54253171647738.
The previous prime is 54253171647707. The next prime is 54253171647749. The reversal of 54253171647739 is 93774617135245.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54253171647739 - 25 = 54253171647707 is a prime.
It is a super-3 number, since 3×542531716477393 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (54253171647749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27126585823869 + 27126585823870.
It is an arithmetic number, because the mean of its divisors is an integer number (27126585823870).
Almost surely, 254253171647739 is an apocalyptic number.
54253171647739 is a deficient number, since it is larger than the sum of its proper divisors (1).
54253171647739 is an equidigital number, since it uses as much as digits as its factorization.
54253171647739 is an evil number, because the sum of its binary digits is even.
The product of its digits is 133358400, while the sum is 64.
The spelling of 54253171647739 in words is "fifty-four trillion, two hundred fifty-three billion, one hundred seventy-one million, six hundred forty-seven thousand, seven hundred thirty-nine".
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